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+#+TITLE: Analysis of the risk of failure of the O-rings on the Challenger shuttle
+#+AUTHOR: Arnaud Legrand
+#+LANGUAGE: fr
+
+#+HTML_HEAD:
+#+HTML_HEAD:
+#+HTML_HEAD:
+#+HTML_HEAD:
+#+HTML_HEAD:
+#+HTML_HEAD:
+
+#+LATEX_HEADER: \usepackage{a4}
+#+LATEX_HEADER: \usepackage[french]{babel}
+
+# #+PROPERTY: header-args :session :exports both
+
+On January 27, 1986, the day before the takeoff of the shuttle /Challenger/, had
+a three-hour teleconference was held between
+Morton Thiokol (the manufacturer of one of the engines) and NASA. The
+discussion focused on the consequences of the
+temperature at take-off of 31°F (just below
+0°C) for the success of the flight and in particular on the performance of the
+O-rings used in the engines. Indeed, no test
+had been performed at this temperature.
+
+The following study takes up some of the analyses carried out that
+night with the objective of assessing the potential influence of
+the temperature and pressure to which the O-rings are subjected
+on their probability of malfunction. Our starting point is
+the results of the experiments carried out by NASA engineers
+during the six years preceding the launch of the shuttle
+Challenger.
+
+* Loading the data
+We start by loading this data:
+#+begin_src python :results value :session *python* :exports both
+import numpy as np
+import pandas as pd
+data = pd.read_csv("shuttle.csv")
+data
+#+end_src
+
+#+RESULTS:
+#+begin_example
+ Date Count Temperature Pressure Malfunction
+0 4/12/81 6 66 50 0
+1 11/12/81 6 70 50 1
+2 3/22/82 6 69 50 0
+3 11/11/82 6 68 50 0
+4 4/04/83 6 67 50 0
+5 6/18/82 6 72 50 0
+6 8/30/83 6 73 100 0
+7 11/28/83 6 70 100 0
+8 2/03/84 6 57 200 1
+9 4/06/84 6 63 200 1
+10 8/30/84 6 70 200 1
+11 10/05/84 6 78 200 0
+12 11/08/84 6 67 200 0
+13 1/24/85 6 53 200 2
+14 4/12/85 6 67 200 0
+15 4/29/85 6 75 200 0
+16 6/17/85 6 70 200 0
+17 7/2903/85 6 81 200 0
+18 8/27/85 6 76 200 0
+19 10/03/85 6 79 200 0
+20 10/30/85 6 75 200 2
+21 11/26/85 6 76 200 0
+22 1/12/86 6 58 200 1
+#+end_example
+
+The data set shows us the date of each test, the number of O-rings
+(there are 6 on the main launcher), the
+temperature (in Fahrenheit) and pressure (in psi), and finally the
+number of identified malfunctions.
+
+* Graphical inspection
+Flights without incidents do not provide any information
+on the influence of temperature or pressure on malfunction.
+We thus focus on the experiments in which at least one O-ring was defective.
+
+#+begin_src python :results value :session *python* :exports both
+data = data[data.Malfunction>0]
+data
+#+end_src
+
+#+RESULTS:
+: Date Count Temperature Pressure Malfunction
+: 1 11/12/81 6 70 50 1
+: 8 2/03/84 6 57 200 1
+: 9 4/06/84 6 63 200 1
+: 10 8/30/84 6 70 200 1
+: 13 1/24/85 6 53 200 2
+: 20 10/30/85 6 75 200 2
+: 22 1/12/86 6 58 200 1
+
+We have a high temperature variability but
+the pressure is almost always 200, which should
+simplify the analysis.
+
+How does the frequency of failure vary with temperature?
+#+begin_src python :results output file :var matplot_lib_filename="freq_temp_python.png" :exports both :session *python*
+import matplotlib.pyplot as plt
+
+plt.clf()
+data["Frequency"]=data.Malfunction/data.Count
+data.plot(x="Temperature",y="Frequency",kind="scatter",ylim=[0,1])
+plt.grid(True)
+
+plt.savefig(matplot_lib_filename)
+print(matplot_lib_filename)
+#+end_src
+
+#+RESULTS:
+[[file:freq_temp_python.png]]
+
+At first glance, the dependence does not look very important, but let's try to
+estimate the impact of temperature $t$ on the probability of O-ring malfunction.
+
+* Estimation of the temperature influence
+
+Suppose that each of the six O-rings is damaged with the same
+probability and independently of the others and that this probability
+depends only on the temperature. If $p(t)$ is this probability, the
+number $D$ of malfunctioning O-rings during a flight at
+temperature $t$ follows a binomial law with parameters $n=6$ and
+$p=p(t)$. To link $p(t)$ to $t$, we will therefore perform a
+logistic regression.
+
+#+begin_src python :results value :session *python* :exports both
+import statsmodels.api as sm
+
+data["Success"]=data.Count-data.Malfunction
+data["Intercept"]=1
+
+
+# logit_model=sm.Logit(data["Frequency"],data[["Intercept","Temperature"]]).fit()
+logmodel=sm.GLM(data['Frequency'], data[['Intercept','Temperature']], family=sm.families.Binomial(sm.families.links.logit)).fit()
+
+logmodel.summary()
+#+end_src
+
+#+RESULTS:
+#+begin_example
+ Generalized Linear Model Regression Results
+==============================================================================
+Dep. Variable: Frequency No. Observations: 7
+Model: GLM Df Residuals: 5
+Model Family: Binomial Df Model: 1
+Link Function: logit Scale: 1.0
+Method: IRLS Log-Likelihood: -3.6370
+Date: Fri, 20 Jul 2018 Deviance: 3.3763
+Time: 16:56:08 Pearson chi2: 0.236
+No. Iterations: 5
+===============================================================================
+ coef std err z P>|z| [0.025 0.975]
+-------------------------------------------------------------------------------
+Intercept -1.3895 7.828 -0.178 0.859 -16.732 13.953
+Temperature 0.0014 0.122 0.012 0.991 -0.238 0.240
+===============================================================================
+#+end_example
+
+The most likely estimator of the temperature parameter is 0.0014
+and the standard error of this estimator is 0.122, in other words we
+cannot distinguish any particular impact and we must take our
+estimates with caution.
+
+* Estimation of the probability of O-ring malfunction
+The expected temperature on the take-off day is 31°F. Let's try to
+estimate the probability of O-ring malfunction at
+this temperature from the model we just built:
+
+#+begin_src python :results output file :var matplot_lib_filename="proba_estimate_python.png" :exports both :session *python*
+import matplotlib.pyplot as plt
+
+data_pred = pd.DataFrame({'Temperature': np.linspace(start=30, stop=90, num=121), 'Intercept': 1})
+data_pred['Frequency'] = logmodel.predict(data_pred)
+data_pred.plot(x="Temperature",y="Frequency",kind="line",ylim=[0,1])
+plt.scatter(x=data["Temperature"],y=data["Frequency"])
+plt.grid(True)
+
+plt.savefig(matplot_lib_filename)
+print(matplot_lib_filename)
+#+end_src
+
+#+RESULTS:
+[[file:proba_estimate_python.png]]
+
+As expected from the initial data, the
+temperature has no significant impact on the probability of failure of the
+O-rings. It will be about 0.2, as in the tests
+where we had a failure of at least one joint. Let's get back to the initial dataset to estimate the probability of failure:
+
+#+begin_src python :results output :session *python* :exports both
+data = pd.read_csv("shuttle.csv")
+print(np.sum(data.Malfunction)/np.sum(data.Count))
+#+end_src
+
+#+RESULTS:
+: 0.06521739130434782
+
+This probability is thus about $p=0.065$. Knowing that there is
+a primary and a secondary O-ring on each of the three parts of the
+launcher, the probability of failure of both joints of a launcher
+is $p^2 \approx 0.00425$. The probability of failure of any one of the
+launchers is $1-(1-p^2)^3 \approximately 1.2%$. That would really be
+bad luck.... Everything is under control, so the takeoff can happen
+tomorrow as planned.
+
+But the next day, the Challenger shuttle exploded and took away
+with her the seven crew members. The public was shocked and in
+the subsequent investigation, the reliability of the
+O-rings was questioned. Beyond the internal communication problems
+of NASA, which have a lot to do with this fiasco, the previous analysis
+includes (at least) a small problem.... Can you find it?
+You are free to modify this analysis and to look at this dataset
+from all angles in order to to explain what's wrong.
+