From d4833a804ef7346567738a24b995aa77241f644c Mon Sep 17 00:00:00 2001 From: d38d5486f40eba2af6d1e02f32199f18 Date: Tue, 29 Aug 2023 12:43:15 +0000 Subject: [PATCH] essai --- module2/exo1/toy_notebook_fr.ipynb | 116 ++++++++++++++++++++++++++++- 1 file changed, 113 insertions(+), 3 deletions(-) diff --git a/module2/exo1/toy_notebook_fr.ipynb b/module2/exo1/toy_notebook_fr.ipynb index 0bbbe37..962ff00 100644 --- a/module2/exo1/toy_notebook_fr.ipynb +++ b/module2/exo1/toy_notebook_fr.ipynb @@ -1,5 +1,116 @@ { - "cells": [], + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# toy_ntebook_fr" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "March 28, 2019" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "\n", + "## A propos du calcul de 'pi'" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "\n", + "### En demandant à la lib maths\n" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Mon ordinateur m'indique que pi vaut approximativement" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "scrolled": true + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "3.141592653589793\n" + ] + } + ], + "source": [ + "from math import *\n", + "print(pi)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### En utilisant la méthode des aiguilles de Buffon" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Mais calculé avec la méthode des aiguilles de Buffon, on obtiendrait comme approximation" + ] + }, + { + "cell_type": "code", + "execution_count": 5, + "metadata": {}, + "outputs": [ + { + "data": { + "text/plain": [ + "3.128911138923655" + ] + }, + "execution_count": 5, + "metadata": {}, + "output_type": "execute_result" + } + ], + "source": [ + "import numpy as np\n", + "np.random.seed(seed=42)\n", + "N=10000\n", + "x=np.random.uniform(size=N, low=0, high=1)\n", + "theta=np.random.uniform(size=N, low=0, high=pi/2)\n", + "2/(sum((x+np.sin(theta))>1)/N)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "### Avec un argument \"fréquentiel\" de surface" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "Sinon, une méthode plus simple à comprendre et ne faisant pas intervenir d'appel à la fonction sinus se base sur le fait que si X" + ] + } + ], "metadata": { "kernelspec": { "display_name": "Python 3", @@ -16,10 +127,9 @@ "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", - "version": "3.6.3" + "version": "3.6.4" } }, "nbformat": 4, "nbformat_minor": 2 } - -- 2.18.1