From 68d94d1752d4f3ea77e769493086fd19d481d98e Mon Sep 17 00:00:00 2001 From: feee8ecec645c53ceeda57e948ea51be Date: Fri, 23 Jul 2021 22:10:45 +0000 Subject: [PATCH] Update toy_document_en.Rmd --- module2/exo1/toy_document_en.Rmd | 49 +++++++++++++++++++------------- 1 file changed, 30 insertions(+), 19 deletions(-) diff --git a/module2/exo1/toy_document_en.Rmd b/module2/exo1/toy_document_en.Rmd index 13b258d..42a848f 100644 --- a/module2/exo1/toy_document_en.Rmd +++ b/module2/exo1/toy_document_en.Rmd @@ -1,33 +1,44 @@ --- -title: "Your title" -author: "Your name" -date: "Today's date" +title: "On the computation of pi" +author: "Gkiouzepi Eleni" +date: "23/7/2021" output: html_document --- +## Asking the math library -```{r setup, include=FALSE} -knitr::opts_chunk$set(echo = TRUE) -``` +My computer me that $\pi$ is *approximatively* -## Some explanations +```{r} +pi +``` -This is an R Markdown document that you can easily export to HTML, PDF, and MS Word formats. For more information on R Markdown, see . +## Buffon's needle -When you click on the button **Knit**, the document will be compiled in order to re-execute the R code and to include the results into the final document. As we have shown in the video, R code is inserted as follows: +Applying the method of [Buffon's needle](https://en.wikipedia.org/wiki/Buffon%27s_needle_problem) we get the **aproximation** -```{r cars} -summary(cars) +```{r} +set.seed(42) +N = 100000 +x = runif(N) +theta = pi/2*runif(N) +2/(mean(x+sin(theta)>1)) ``` -It is also straightforward to include figures. For example: - -```{r pressure, echo=FALSE} -plot(pressure) -``` +## Using a surface fraction argument -Note the parameter `echo = FALSE` that indicates that the code will not appear in the final version of the document. We recommend not to use this parameter in the context of this MOOC, because we want your data analyses to be perfectly transparent and reproducible. +A method that is easier to understand and does not make use of the $\sin$ function is based on the fact that if $X∼U(0,1)$ and $Y∼U(0,1)$, then $P[X^2+Y^2 \le 1]=\pi/4$ (see ["Monte Carlo method" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code use this approach: -Since the results are not stored in Rmd files, you should generate an HTML or PDF version of your exercises and commit them. Otherwise reading and checking your analysis will be difficult for anyone else but you. +```{r} +set.seed(42) +N = 1000 +df = data.frame(X = runif(N), Y = runif(N)) +df$Accept = (df$X**2 + df$Y**2 <=1) +library(ggplot2) +ggplot(df, aes(x=X,y=Y,color=Accept)) + geom_point(alpha=.2) + coord_fixed() + theme_bw() +``` +It is therefore straightforward to obtain a (not really good) approximation to π by counting how many times, on average, $X^2+Y^2$ is smaller than 1 : -Now it's your turn! You can delete all this information and replace it by your computational document. +```{r} +4*mean(df$Accept) +``` -- 2.18.1