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06295db534a9872198b1363b8b12f920
mooc-rr
Commits
071fc0a9
Commit
071fc0a9
authored
Mar 06, 2025
by
06295db534a9872198b1363b8b12f920
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test
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272867e7
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toy_notebook_en.ipynb
module2/exo1/toy_notebook_en.ipynb
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module2/exo1/toy_notebook_en.ipynb
View file @
071fc0a9
...
...
@@ -70,7 +70,7 @@
"## 1.3 Using a surface fraction argument\n",
"\n",
"A method that is easier to understand and does not make use of the sin function is based on the\n",
"fact that if *X ∼ U(0, 1)* and *Y ∼ U(0, 1)* then P[X
^2 + Y^2
≤ 1] = π/4 (see [\"Monte Carlo method\"\n",
"fact that if *X ∼ U(0, 1)* and *Y ∼ U(0, 1)* then P[X
<sup>2</sup> + Y<sup>2</sup>
≤ 1] = π/4 (see [\"Monte Carlo method\"\n",
"on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
]
},
...
...
@@ -108,6 +108,16 @@
"ax.set_aspect('equal')\n"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"It is then straightforward to obtain a (not really good) approximation to π by counting how\n",
"many times, on average, X<sup>2</sup> + Y<sup>2</sup> is smaller than 1:"
]
},
{
"cell_type": "code",
"execution_count": 4,
...
...
@@ -125,25 +135,7 @@
}
],
"source": [
"4*np.mean(accept)\n"
]
},
{
"cell_type": "code",
"execution_count": 6,
"metadata": {},
"outputs": [
{
"ename": "SyntaxError",
"evalue": "invalid syntax (<ipython-input-6-2b522dbd7382>, line 1)",
"output_type": "error",
"traceback": [
"\u001b[0;36m File \u001b[0;32m\"<ipython-input-6-2b522dbd7382>\"\u001b[0;36m, line \u001b[0;32m1\u001b[0m\n\u001b[0;31m 4*np.mean(accept.5f)\u001b[0m\n\u001b[0m ^\u001b[0m\n\u001b[0;31mSyntaxError\u001b[0m\u001b[0;31m:\u001b[0m invalid syntax\n"
]
}
],
"source": [
"\n"
"4*np.mean(accept)"
]
},
{
...
...
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