update

parent 8211c0c4
......@@ -4,8 +4,13 @@
"cell_type": "markdown",
"metadata": {},
"source": [
"# On the computation of $\\pi$\n",
"\n",
"# On the computation of $\\pi$"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Asking the maths library\n",
"My computer tells me that $\\pi$ is *approximatively*"
]
......@@ -33,7 +38,7 @@
"metadata": {},
"source": [
"## Buffon's needle\n",
"Applying the method of [Buffon's needle](https://en.wikipedia.org/wiki/Buffon%27s_needle_problem), we get the _approximation_"
"Applying the method of [Buffon's needle](https://en.wikipedia.org/wiki/Buffon%27s_needle_problem), we get the __approximation__"
]
},
{
......@@ -69,7 +74,7 @@
"source": [
"## Using a surface fraction argument\n",
"A method that is easier to understand and does not make use of the sin function is based on the \n",
"fact that if X ~ *U*(0,1) and Y ~ *U*(0,1), then $P[X^2+Y^2\\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
"fact that if $X\\sim U(0,1)$ and $Y\\sim U(0,1)$, then $P[X^2+Y^2\\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
]
},
{
......
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