update

parent 8211c0c4
...@@ -4,8 +4,13 @@ ...@@ -4,8 +4,13 @@
"cell_type": "markdown", "cell_type": "markdown",
"metadata": {}, "metadata": {},
"source": [ "source": [
"# On the computation of $\\pi$\n", "# On the computation of $\\pi$"
"\n", ]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Asking the maths library\n", "## Asking the maths library\n",
"My computer tells me that $\\pi$ is *approximatively*" "My computer tells me that $\\pi$ is *approximatively*"
] ]
...@@ -33,7 +38,7 @@ ...@@ -33,7 +38,7 @@
"metadata": {}, "metadata": {},
"source": [ "source": [
"## Buffon's needle\n", "## Buffon's needle\n",
"Applying the method of [Buffon's needle](https://en.wikipedia.org/wiki/Buffon%27s_needle_problem), we get the _approximation_" "Applying the method of [Buffon's needle](https://en.wikipedia.org/wiki/Buffon%27s_needle_problem), we get the __approximation__"
] ]
}, },
{ {
...@@ -69,7 +74,7 @@ ...@@ -69,7 +74,7 @@
"source": [ "source": [
"## Using a surface fraction argument\n", "## Using a surface fraction argument\n",
"A method that is easier to understand and does not make use of the sin function is based on the \n", "A method that is easier to understand and does not make use of the sin function is based on the \n",
"fact that if X ~ *U*(0,1) and Y ~ *U*(0,1), then $P[X^2+Y^2\\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:" "fact that if $X\\sim U(0,1)$ and $Y\\sim U(0,1)$, then $P[X^2+Y^2\\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
] ]
}, },
{ {
......
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