"My computer tells me that $\\pi$ is *approximatively*"
"My computer tells me that $\\pi$ is *approximatively*"
]
]
},
},
...
@@ -43,13 +37,7 @@
...
@@ -43,13 +37,7 @@
"cell_type": "markdown",
"cell_type": "markdown",
"metadata": {},
"metadata": {},
"source": [
"source": [
"## Buffon’s needle"
"## Buffon’s needle\n",
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Applying the method of [Buffon’s needle](https://en.wikipedia.org/wiki/Buffon's_needle_problem), we get the **approximation**"
"Applying the method of [Buffon’s needle](https://en.wikipedia.org/wiki/Buffon's_needle_problem), we get the **approximation**"
]
]
},
},
...
@@ -82,13 +70,7 @@
...
@@ -82,13 +70,7 @@
"cell_type": "markdown",
"cell_type": "markdown",
"metadata": {},
"metadata": {},
"source": [
"source": [
"## Using a surface fraction argument"
"## Using a surface fraction argument\n",
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"A method that is easier to understand and does not make use of the sin function is based on the fact that if $X \\sim U(0,1)$ and $Y \\sim U(0,1)$, then $P[X^{2} +Y^{2} \\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
"A method that is easier to understand and does not make use of the sin function is based on the fact that if $X \\sim U(0,1)$ and $Y \\sim U(0,1)$, then $P[X^{2} +Y^{2} \\leq 1] = \\pi/4$ (see [\"Monte Carlo method\" on Wikipedia](https://en.wikipedia.org/wiki/Monte_Carlo_method)). The following code uses this approach:"
