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Commit 2f558eee authored by 8388c1425d3a684d1ec014af187ba020's avatar 8388c1425d3a684d1ec014af187ba020
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Update toy_document_orgmode_python_en.org

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module2/exo1/toy_document_orgmode_python_en.org
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...@@ -24,8 +24,6 @@ from math import * ...@@ -24,8 +24,6 @@ from math import *
pi pi
#+end_src #+end_src
#+RESULTS:
* 2. *Buffon's needle * 2. *Buffon's needle
Applying the method of [[https://en.wikipedia.org/wiki/Buffon%27s_needle_problem][_Buffon's needle_]], we get the *approximation* Applying the method of [[https://en.wikipedia.org/wiki/Buffon%27s_needle_problem][_Buffon's needle_]], we get the *approximation*
#+begin_src python :results output :exports both #+begin_src python :results output :exports both
...@@ -37,7 +35,7 @@ theta=np.random.uniform(size=N, low=0, high = pi/2) ...@@ -37,7 +35,7 @@ theta=np.random.uniform(size=N, low=0, high = pi/2)
2/(sum((x+np.sin(theta))>1)/N) 2/(sum((x+np.sin(theta))>1)/N)
#+end_src #+end_src
#+RESULTS:
* 3. Using a surface fraction argument * 3. Using a surface fraction argument
A method that is easier to understand and does not make use of the sin A method that is easier to understand and does not make use of the sin
...@@ -65,7 +63,7 @@ plt.savefig(matplot_lib_filename) ...@@ -65,7 +63,7 @@ plt.savefig(matplot_lib_filename)
print(matplot_lib_filename) print(matplot_lib_filename)
#+end_src #+end_src
#+RESULTS:
It is then straightforward to obtain a (not really good) approximation It is then straightforward to obtain a (not really good) approximation
of \pi by counting how many time, on average, $X^2$ + $^{}Y^2$ is smaller of \pi by counting how many time, on average, $X^2$ + $^{}Y^2$ is smaller
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