Ajout de la méthode de calcul des aiguilles de Buffon

parent 5d14350b
...@@ -7,22 +7,75 @@ ...@@ -7,22 +7,75 @@
"# A propos du calcul de $\\pi$" "# A propos du calcul de $\\pi$"
] ]
}, },
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## En demandant à la lib maths"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Mon ordianteur m'indique que $\\pi$ vaut _approximativement_"
]
},
{ {
"cell_type": "code", "cell_type": "code",
"execution_count": 1, "execution_count": 2,
"metadata": {}, "metadata": {},
"outputs": [ "outputs": [
{ {
"name": "stdout", "name": "stdout",
"output_type": "stream", "output_type": "stream",
"text": [ "text": [
"[1] 10\n" "3.141592653589793\n"
] ]
} }
], ],
"source": [ "source": [
"x = 10\n", "from math import *\n",
"print(x)" "print(pi)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## En utilisant la méthode des aiguilles de Buffon"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Mais calculé avec la **méthode** des (aiguilles de Buffon)[https://fr.wikipedia.org/wiki/Aiguille_de_Buffon], on obitendrait comme **approximation** :"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"3.128911138923655"
]
},
"execution_count": 3,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"import numpy as np\n",
"np.random.seed(seed=42)\n",
"N = 10000\n",
"x = np.random.uniform(size=N, low=0, high=1)\n",
"theta = np.random.uniform(size=N, low=0, high=pi/2)\n",
"2/(sum((x+np.sin(theta))>1)/N)"
] ]
}, },
{ {
......
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