essai

parent e391755a
{
"cells": [],
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# toy_ntebook_fr"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"March 28, 2019"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"\n",
"## A propos du calcul de 'pi'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"\n",
"### En demandant à la lib maths\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Mon ordinateur m'indique que pi vaut approximativement"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"scrolled": true
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"3.141592653589793\n"
]
}
],
"source": [
"from math import *\n",
"print(pi)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### En utilisant la méthode des aiguilles de Buffon"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Mais calculé avec la méthode des aiguilles de Buffon, on obtiendrait comme approximation"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {},
"outputs": [
{
"data": {
"text/plain": [
"3.128911138923655"
]
},
"execution_count": 5,
"metadata": {},
"output_type": "execute_result"
}
],
"source": [
"import numpy as np\n",
"np.random.seed(seed=42)\n",
"N=10000\n",
"x=np.random.uniform(size=N, low=0, high=1)\n",
"theta=np.random.uniform(size=N, low=0, high=pi/2)\n",
"2/(sum((x+np.sin(theta))>1)/N)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"### Avec un argument \"fréquentiel\" de surface"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Sinon, une méthode plus simple à comprendre et ne faisant pas intervenir d'appel à la fonction sinus se base sur le fait que si X"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
......@@ -16,10 +127,9 @@
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.6.3"
"version": "3.6.4"
}
},
"nbformat": 4,
"nbformat_minor": 2
}
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