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ee86fa7a3582ca7f1b880e3ab22059ce
mooc-rr
Commits
c9e18170
Commit
c9e18170
authored
Jun 09, 2021
by
ee86fa7a3582ca7f1b880e3ab22059ce
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change of math
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c26a9894
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toy_notebook_en.ipynb
module2/exo1/toy_notebook_en.ipynb
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module2/exo1/toy_notebook_en.ipynb
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c9e18170
...
...
@@ -8,7 +8,7 @@
"\n",
"March 28, 2019\n",
"\n",
"# 1 On the computation of
π
\n",
"# 1 On the computation of
$\\pi$
\n",
"\n",
"## 1.1 Asking the maths library\n",
"\n",
...
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@@ -73,8 +73,8 @@
"## 1.3 Using a surface fraction argument\n",
"\n",
"A method that is easier to understand and does not make use of the sin function is based on the\n",
"fact that if
X ∼ U ( 0, 1 ) and Y ∼ U ( 0, 1 ) , then P [ X 2 + Y 2 ≤ 1 ] = π/4 (see (\"
Monte Carlo method\"\n",
"on Wikipedia
)[https://en.wikipedia.org/wiki/Monte_Carlo_method]
). The following code uses this approach:"
"fact that if
$X\\sim U(0,1)$ and $Y\\sim U(0,1)$ then $P[X^2+Y^2\\leq 1] = \\pi/4$ (see (\"[
Monte Carlo method\"\n",
"on Wikipedia
](https://en.wikipedia.org/wiki/Monte_Carlo_method)
). The following code uses this approach:"
]
},
{
...
...
@@ -115,8 +115,8 @@
"cell_type": "markdown",
"metadata": {},
"source": [
"It is then straightforward to obtain a (not really good) approximation to
π
by counting how\n",
"many times, on average,
X 2 + Y 2
is smaller than 1:"
"It is then straightforward to obtain a (not really good) approximation to
$\\pi$
by counting how\n",
"many times, on average,
$X^2 + Y^2$
is smaller than 1:"
]
},
{
...
...
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